It is possible to calculate it to cover all the
fees. The easiest way to see it is to think about
it this way. . . Say someone needs to send you
$10. But they're a pal and want to cover the fees.
If they sent you $100, that would very definitely
cover the original $10 and *all* the fees incurred
from that $10, including the fees on the part of
the payment that was the fee. Correct? As a matter
of fact, you would have a lot over the top. So
that means that there is a mathematical point
between $10 and $100 at which the original amount
and all the fees are completely covered.
For a realistic example, I needed to send $15.04
to one of my Hard Rock Cafe people who can accept
Paypal only from a funded account. The amount I
needed to send to my husband's account had to be
enough to cover both the $15.04 that I needed to
send - and the fees incurred by sending it. (Send
too little, I wouldn't have the full $15.04 to
send back out.) So, after some math, I decided on
$16. Even after the fees, there was $15.04 in the
account. (And an extra $.24 - hey, my late night
math has always sucked. ^_^;) In any case, if
this were someone else who owed me $15.04 for
something, then it's plain and simple that them
sending $16 (or even $15.76) would have paid the
fees and left me with the full amount owed to me.
I think you're thinking of the hypothetical joke
question about the naked girl. . . Which is (in
case people don't know it):
Ask a (male, I've alwyas assumed) mathematician
and a scientist if they would be excited to walk
up to a naked girl with the only constraint being
that each time they moved forward, they could
only close half the distance. The mathematician
says: "Forget it - if you can only ever close the
distance by half, you'll never get there." The
scientist jumps forward eagerly saying: "I might
never get there, but I'll get close enough for
the distance left to make no odds." ^_~
The difference between the naked girl question
and the way Paypal works is division versus
multiplication. That's why you can cover the
(financial) distance in one, but not the (spacial)
distance in the other. ^_^
Many Sharp Smiles,
--Drac (back to cleaning so wndrkn doesn't see
I'm a slob. . . ^_^;;;;;)
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